In: Statistics and Probability
3) A stock market analyst wants to determine if the recent Hotel C upgrade to 4 starts has changed the distribution of shares of the hotel market. The current market share for the existing 3 hotels is shown in table below. The analyst collects data from a random sample of 200 investors. The table below shows the observed investors’ share holdings (fi ). When using this random sample the analyst needs to be 90% confident of test results. The hypothesis to be tested follows:
H0 : Pa =0.25; Pb =0.45; Pc =0.30 ; market shares have remained same
Ha : Pa ≠0.25; Pb ≠0.45; Pc ≠0.30 ; market shares have changed
Hotel Name |
Current Market Share |
Observ. Freq fi |
||||
A |
0.25 |
50 |
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B |
0.45 |
95 |
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C |
0.30 |
55 |
||||
Totals |
200 |
B. Has the recent upgrade of Hotel C to 5 stars changed the hotel market composition? Why?
( a )
The following table is obtained:
Categories | Observed | Expected | (fo-fe)2/fe |
Category 1 | 50 | 200*0.25=50 | (50-50)2/50 = 0 |
Category 2 | 95 | 200*0.45=90 | (95-90)2/90 = 0.278 |
Category 3 | 55 | 200*0.30=60 | (55-60)2/60 = 0.417 |
Sum = | 200 | 200 | 0.694 |
from the above calculated table
Test Statistics
Rejection Region
Based on the information provided, the significance level is α = 0.10, the number of degrees of freedom is df = 3−1 = 2, so then the rejection region for this test is R = { χ2:χ2 > 4.605}.
Decision about the null hypothesis
Since it is observed that χ2 = 0.694 ≤ χc2 = 4.605, it is then concluded that the null hypothesis is not rejected.
( b )
No the recent upgrade of Hotel C to 5 stars does not changed the hotel market composition . Because the null hypothesis is not rejected. so market shares have remained same and also Hotel C.