A reaction released 1256 J of heat and expands from 1.3L to 14.7L at a constant...

A reaction released 1256 J of heat and expands from 1.3L to 14.7L at a constant pressure of 1.04 kPa. What is the total energy change for the system in kJ. Include the correct sign with respect to the system. (1 kPa * L = 1 J)

Expert Solution

The amount of heat released , Q = -1256 J

Work done by the system , W = - PdV

= -1.04 kPa x ( 14.7 - 1.3) L

= - 1.04 x 13.4 KPa L

= - 13.9 J

From first law of thermodynamics Q = dE + W

Here dE = change in internal energy = ?

dE = Q - W

= -1256 -(-13.9) J

= -1242.1 J

queen_honey_blossom answered 2 months ago

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