In: Statistics and Probability
A company is considering submitting a tender for a job.
Producing the tender will cost the company $1500, which must be
paid even if the company does not win the tender
The company's current expectation of the cost of the project is
that there is a 0.58 probability that the cost is $7700, and
otherwise the cost is $10900. These costs do not include the
cost
of producing the tender.
The company also believes that their is a 0.28 probability that the
lowest competing bid will be $9200, a 0.37 probability that the
lowest competing bid will be $14400, and otherwise the
lowest competing bid will be $12000
In regard to the tender price the company is considering whether it
should bid $10600, bid $13200, or not bid.
You may assume that the probabilities given for the costs of the
project are independent to the probabilities of the values of the
lowest competing bid. Thus if they submit a price of $13200
then the probability that they will make the maximum profit ($13200
- $7700 - $1500 = $4000) is P(winning) * P(low cost) = 0.37 *
0.58.
Draw a decision tree that represents this
situation and show all EMVs and probabilities. Indicate
selection of decision options with probability = 1 for
preferred
options and probability = 0 for rejected options.
Monetary values should be answered to the nearest dollar.
Probabilities should be answered to three decimal
places.
The company is coonsidering 3 choices
The company will lose the tender if the lowest competing bid is less than $10,600. The probability that competing bid is less than $10,600 is the (probability that the lowest competing bid is 9200) = 0.28. This is the probability of losing the tender. The probability of winning = 1- 0.28=0.72
If it bids, then the cost of tender is $1500. If it wins then the cost of the project may be low($7700) with a probability of 0.58 or it could be high ($10900) with a probability of 0.42
The following is the decision tree
We move from right to left of the decison tree
Chance node 4:
EMV(node 4)= (payoff when high cost)*(probability of high cost) +(payoff when low cost)*(probability of low cost) = -1800*0.42+1400*0.58 = $56
Chance node 5:
EMV(node 5)= (payoff when high cost)*(probability of high cost) +(payoff when low cost)*(probability of low cost) = 800*0.42+4000*0.58 = $2656
Chance node 2:
EMV(node 2) = (payoff if win)*(probability of winning) +(payoff when lose)*(probability of losing) = 56*0.72-1500*0.28 = -$380
Chance node 3:
EMV(node 3) = (payoff if win)*(probability of winning) +(payoff when lose)*(probability of losing) = 2656*0.37-1500*0.63 = $38
At node 1 the copany has 3 choices.
Since bidding $13200 gives the highest expected monitory value of $38, the company should bid at $13,200