Question

A food safety guideline is that the mercury in fish should be below 1 part per million​ (ppm). Listed below are the amounts of mercury​ (ppm) found in tuna sushi sampled at different stores in a major city. Construct a 90​% confidence interval estimate of the mean amount of mercury in the population. Does it appear that there is too much mercury in tuna​ sushi? 0.60  0.69  0.09  0.94  1.31  0.56  0.92

What is the confidence interval estimate of the population mean mu​?

Answer 1

population mean	μ=	1343
sample mean	x=	0.73
sample size	n=	7
sample std deviation	s=	0.38
standard errror of mean =	s=s/√n=	0.1442

for 90% CI; and 6 degree of freedom, value of t=					1.9430
margin of error E=t*std error                            =					0.280
lower confidence bound=sample mean-margin of error =					0.450
Upper confidence bound=sample mean+margin of error=					1.010

from above 90% confidence interval for population mean =(0.450, 1.010)