In: Chemistry
A sediment sample taken from a lignite strip-mine pit contains highly alkaline (pH 10) water. Cations were displaced from the sediment by treatment with HCl. A total analysis of cations in the leachate yielded, on the basis of millimoles per 100 g of dry sediment: 160 mmol Na+, 10 mmol K+, 30 mmol Mg2+, and 70 mmol Ca2+. What is the cation exchange capacity of the sediment in milliequivalents per 100 g of dry sediment? Why does H+ not have to be considered in this case?
100 g of dry sediment contains
160 millimoles of Na+ = 160 /1 = 160 meq of Na+ [ since millimoles/valency = milliequivalents]
10 millimoles of K+ = 10 /1 = 10 meq of K+
30 millimoles of Mg2+ = 30 /2 = 15 meq of Mg2+
70 millimoles of Ca2+ = 70/2 = 35 meq of Ca2+
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Total 220 meq of exchangeable cations/100g of dry sediment
Thus the answer CEC = 220 meq/100 g of dry sediment
since the sediment is highly alkaline H+ not have to be considered in this case.