Question
In: Statistics and Probability
A simple random sample was taken of 44 water bottles from a bottling plant’s warehouse. The...
A simple random sample was taken of 44 water bottles from a bottling plant’s warehouse. The dissolved oxygen content (in mg/L) was measured for each bottle, with these results: 11.53, 8.35, 11.66, 11.54, 9.83, 5.92, 7.14, 8.41, 8.99, 13.81, 10.53, 7.4, 6.7, 8.42, 8.4, 8.18, 9.5, 7.22, 9.87, 6.52, 8.55, 9.75, 9.27, 10.61, 8.89, 10.01, 11.17, 7.62, 6.43, 9.09, 8.53, 7.91, 8.13, 7.7, 10.45, 11.3, 10.98, 8.14, 11.48, 8.44, 12.52, 10.12, 8.09, 7.34
Here the sample mean is 9.14 mg/L.
The population standard deviation of the dissolved oxygen content for the warehouse is known from long experience to be about σ = 2 mg/L.
Consider testing H0 : µ = 10 vs. HA : µ 6= 10, where µ is the unknown population mean dissolved oxygen content, at significance level α = .02 (not the usual .05).
(a) A Z test is appropriate here because we have a SRS with a large n. Find the value of the test statistic and the p-value
(b) What conclusion do you reach?
Solutions
orchestra answered 1 year agoRelated Solutions
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