Question

Total internal reflection is behind the ability of optical fibers to send signals over great distances. The are typically formed by a core material of higher index than the "cladding" material that surrounds the core. For an optical fiber with a core index of 1.58 and a cladding index of 1.53. For a ray travelling along the core, what is the minimum angle (in degrees) of incidence against the cladding needed to keep the light in the fiber? 75.55

As light rays follows different paths down the fiber, they traverse different path lengths and therefore take different amounts of time. For an optical fiber with a 0.2 mm core diameter, compare a light ray moving straight down the center versus one reflecting off of the cladding at the critical angle. For 1 m of fiber, how much further than 1 m does the critical ray travel (in cm)?

Answer 1

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