Question

A passenger on a moving train walks at a speed of 1.40 m/s due north relative to the train. The passenger's speed with respect to the ground is 4.5 m/s at an angle of 30.0° west of north. What are the magnitude and direction of the velocity of the train relative to the ground?

magnitude	___ m/s
direction	____ ° west of north

Answer 1

small conducting spherical shell with inner radius a and outer radius b is concentric with a larger conducting spherical shell with inner radius cand outer radius d. The inner shell has a total charge of -1q and the outer shell has a total charge of +4q.

Select True or False for the following statements.
The total charge on the inner surface of the small shell is zero.
The total charge on the inner surface of the large shell is -5q.
The radial component of the electric field in the region r < a is given by -1q/(4πε0r2).
The radial component of the electric field in the region r > d is given by +3q/(4πε0r2).
The radial component of the electric field in the region c < r < d is given by -1q/(4πε0r2).
The total charge on the outer surface of the small shell is -1q.
The total charge on the outer surface of the large shell is +3q.

Here ,

velocity of passenge relative to train ,

Vpt = 1.40 j m/s

velocity of passenger relative to train , Vp = 4.5 *(-cos(60) i + j * sin(60))

Now , let the velocity of train is vt

Vpt = Vp - Vt

1.40 j = 4.5 *(-cos(60) i + j * sin(60)) - Vt

Vt = - 2.25 i + 2.5 j m/s

Now , magnitude of velocity , vt = sqrt(2.25^2 + 2.5^2)

vt = 3.363 m/s

angle = arctan(2.25/2.5)

angle = 42 degree

the magnitude is 3.363 m/s

the direction of train's velocity is 42 degree west of north