The best laboratory vacuum has a pressure of about 1.00 x 10-18 atm, or 1.01 x...

The best laboratory vacuum has a pressure of about 1.00 x 10-18 atm, or 1.01 x 10-13 Pa. How many gas molecules are in 8.57 cm3 in such a vacuum at 298 K?

Expert Solution

Pressure P = 1.01 x10 ^-13 Pa

Volume V = 8.57 x10 ^-6 m ³

Temprature T = 298 K

From the relation PV = nRT

From this number of moles n = PV /RT

Where R = Gas constant = 8.314 J / mol K

Substitute values you get n =(1.01 x10 ^-13 Pa)(8.57 x10 ^-6 m ³) / (8.314 x 298)

= 3.493 x10 ^-22 mol

We know 1 mole = 6.023 x10 ²³ molecules

So, number of gas molecules in given vacuum = n x 6.023 x10 ²³

= 210

genius_generous answered 1 month ago

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