In: Chemistry
For the following half reaction: N2(g) + 5H+(aq)+4e- ----> N2H5+
Calculate the amount of time required to produce 7.86 (g) of N2 while using a 15.0 A current.
weight (W) = 7.86
current (i) = 15 A
faraday (F) = 96500 C
N2 -------------------> N2H5+
0 -2 --------------------> oxidation state of N atom
for 2 N atoms change is oxidation state = -4 (4 units)
equivalence weight of N2 (E) = molecular weight / valency
= 28 /4
= 7 GEW
from faraday law
W = E x i x t / 96500
7.86 = 7 x 15 x t / 96,500
t = 7223.7 sec
t = 120.39 min
time required = t = 7223.7 sec = 120.39 min