In: Chemistry
25. The half-reaction at the anode for the following balanced reaction is: 3MnO4 - (aq) + 5Fe (s) + 24H+ (aq) ¬ 5Fe+3 (aq) + 3Mn+2 (aq) + 12H2O (l)
a. Fe+2 (aq) → Fe+3 (aq) + e -
b. MnO4 - (aq) + 8H+ (aq) + 5 e - → Mn+2 (aq) + 4H2O (l)
c. Fe (s) → Fe+3 (aq) + 3 e -
d. 2MnO4 - (aq) + 12H+ (aq) + 6e→ 2Mn+2 (aq) + 3H2O (l)