In: Statistics and Probability
A company hopes to improve customer satisfaction, setting as a goal no more than 9 % negative comments. A random survey of 320 customers found only 15 with complaints. a) Create a two-sided 95 % confidence interval for the true level of dissatisfaction among customers. b) Does this provide evidence that the company has reached its goal? Using your confidence interval, test an appropriate hypothesis and state your conclusion. a) The 95 % confidence interval for the true level of dissatisfaction among customers is left parenthesis nothing comma nothing right parenthesis . (Round to three decimal places as needed.) b) What are the null and alternative hypotheses? H0: p ▼ equals not equals greater than less than nothing vs. HA: p ▼ equals greater than not equals less than nothing (Type integers or decimals. Do not round.) Use the confidence interval in part a to draw a conclusion. There ▼ is insufficient is sufficient evidence that the true level of dissatisfaction among customers is less than nothing % because nothing is ▼ within the limits above the upper limit below the lower limit of the interval. (Type integers or decimals. Do not round.) Enter your answer in each of the answer boxes.
(a)
We need to construct the 95% confidence interval for the population proportion. We have been provided with the following information about the number of favorable cases:
Favorable Cases X = | 15 |
Sample Size N = | 320 |
The sample proportion is computed as follows, based on the sample sizeN=320 and the number of favorable cases X=15:
The critical value for α=0.05 is . The corresponding confidence interval is computed as shown below:
b)
a). The 95 % confidence interval for the true level of dissatisfaction among customers is (0.024,0.07)
b)
H0: p equals 0.09
vs.
HA: p less than 0.09
There is sufficient evidence that the true level of
dissatisfaction among customers is less than 9% because 9% is
above the upper limit of the interval.
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