4) In fruit fly (Drosophila melanogaster), grayish eye color and wingless bodies are caused by recessive...

4) In fruit fly (Drosophila melanogaster), grayish eye color and wingless bodies are caused by recessive genes located on different chromosomes. Red eyes (gr+) and normal wings (wl+) are dominant to gray eyes (gr) and wingless (wl), respectively. Suppose that a true-breeding male with gray eyes and normal wings is crossed with a true-breeding female with red eyes and wingless. a) What is the genotype and phenotype of the F1? b) If these F1 individuals were allowed to intermate, what would be the phenotypic ratio of the resulting F2 flies?

Expert Solution

Answer 4 :

a) A true breeding male with red eyes and normal wings has genotype (gr+gr+wl+wl+) and a true breeding female with grey eyes and wingless bodies will have genotype (gr gr wl wl). When these two are crossed, the F1 generation will have all organisms with genotype gr+gr wl+wl (Following Mendel's typical dihybrid cross). This is because the F1 generation will inherit one allele from each parent for both the traits. Phenotypically they will have red eyes and normal wings because these are dominant over grey eyes and wingless bodies.

b) When two individuals of F1 Generation of the genotype (gr+gr wl+wl) are allowed to intermate, the following cross shows the resultant F2 generation:

This cross follows the pattern of a typical dihybrid cross of Mendel and has the phenotypic ratio 9:3:3:1

gladiator answered 2 years ago

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