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Title: Titanium Alloy Database Table: Table 5b. Creep and Stress Rupture Properties of Titanium Alloys -...

Title: Titanium Alloy Database
Table: Table 5b. Creep and Stress Rupture Properties of Titanium Alloys - Stress for Creep Extension & Rupture (Metric Units)
alloy type common alloy name alloy alias ASTM grade UNS no. condition product form product thickness (mm) test temperature (°C) rupture time (s) stress to produce 0.1% strain (MPa) stress to produce 0.2% strain (MPa) stress to produce 0.5% strain (MPa) stress to produce 1.0% strain (MPa) stress to produce 2.0% strain (MPa) stress to produce 5.0% strain (MPa) rupture stress (MPa) notes source
Unalloyed & Modified Titanium Unalloyed Gr. 1 CP Grade 1 1 R50250 A NR NR 93 10000 193 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 1 CP Grade 1 1 R50250 A NR NR 150 10000 166 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 1 CP Grade 1 1 R50250 A NR NR 205 10000 145 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 1 CP Grade 1 1 R50250 A NR NR 260 10000 138 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 1 CP Grade 1 1 R50250 A NR NR 315 10000 124 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 2 CP Grade 2 2 R50400 A NR NR 93 10000 262 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 2 CP Grade 2 2 R50400 A NR NR 150 10000 228 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 2 CP Grade 2 2 R50400 A NR NR 205 10000 200 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 2 CP Grade 2 2 R50400 A NR NR 260 10000 179 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 2 CP Grade 2 2 R50400 A NR NR 315 10000 159 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 3 CP Grade 3 3 R50550 A NR NR 27 10 275 331 400 448 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 3 CP Grade 3 3 R50550 A NR NR 27 100 214 241 290 310 366 428 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 3 CP Grade 3 3 R50550 A NR NR 27 1000 221 234 317 400 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 3 CP Grade 3 3 R50550 A NR NR 425 10 34 55 69 90 117 138 152 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 3 CP Grade 3 3 R50550 A NR NR 425 100 28 34 48 55 69 83 110 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 3 CP Grade 3 3 R50550 A NR NR 425 1000 28 31 34 62 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 3 CP Grade 3 3 R50550 A NR NR 540 10 17 21 26 48 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 3 CP Grade 3 3 R50550 A NR NR 540 100 7 10 17 33 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 3 CP Grade 3 3 R50550 A NR NR 540 1000 7 19 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 4 CP Grade 4 4 R50700 A NR NR 25 10 366 393 428 490 531 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 4 CP Grade 4 4 R50700 A NR NR 25 100 338 345 366 428 497 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 4 CP Grade 4 4 R50700 A NR NR 25 1000 255 283 310 359 462 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 4 CP Grade 4 4 R50700 A NR NR 370 1 186 207 228 234 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 4 CP Grade 4 4 R50700 A NR NR 370 10 152 186 214 221 228 228 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 4 CP Grade 4 4 R50700 A NR NR 370 100 124 145 172 193 214 228 221 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 4 CP Grade 4 4 R50700 A NR NR 370 1000 97 110 124 138 159 179 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 4 CP Grade 4 4 R50700 A NR NR 425 1 117 138 172 207 221 221 221 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 4 CP Grade 4 4 R50700 A NR NR 425 10 69 90 124 145 159 179 193 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 4 CP Grade 4 4 R50700 A NR NR 425 100 62 55 76 90 97 117 138 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 4 CP Grade 4 4 R50700 A NR NR 425 1000 41 48 55 69 90 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 4 CP Grade 4 4 R50700 A NR NR 540 10 7 22 28 33 38 48 69 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 4 CP Grade 4 4 R50700 A NR NR 540 100 21 26 35 52 ASM
Unalloyed & Modified Titanium Unalloyed Gr. 4 CP Grade 4 4 R50700 A NR NR 540 1000 16 36 ASM
Unalloyed & Modified Titanium Ti-Ni-Mo CP Grade 12 12 R53400 A NR NR 250 1000 221 297 ASM
Alpha & Near-Alpha Ti-3Al-2.5V Ti Grade 9 9 R56320 A NR NR 250 1000 400 421 ASM
Alpha-Beta Ti-4Al-4Mo-2Sn Ti-550, IMI NR bar NR 400 10 607 621 917 ASM
Alpha-Beta Ti-4Al-4Mo-2Sn Ti-550, IMI NR bar NR 400 100 517 572 910 ASM
Alpha-Beta Ti-4Al-4Mo-2Sn Ti-550, IMI NR bar NR 400 1000 414 483 876 ASM
Alpha-Beta Ti-4Al-4Mo-2Sn Ti-550, IMI NR bar NR 450 10 359 428 835 ASM
Alpha-Beta Ti-4Al-4Mo-2Sn Ti-550, IMI NR bar NR 450 100 248 310 821 ASM
Alpha-Beta Ti-4Al-4Mo-2Sn Ti-550, IMI NR bar NR 450 1000 138 193 655 ASM
Alpha-Beta Ti-4Al-4Mo-2Sn Ti-550, IMI NR bar NR 500 10 172 662 ASM
Alpha-Beta Ti-4Al-4Mo-2Sn Ti-550, IMI NR bar NR 500 100 90 517 ASM
Alpha-Beta Ti-4Al-4Mo-2Sn Ti-550, IMI NR bar NR 500 1000 28 241 ASM
Alpha-Beta Ti-6Al-4V Titanium Grade 5; Ti-6-4 5 R56400 A NR NR 400 100 276 331 483 524 635 662 ASM
Alpha-Beta Ti-6Al-4V Titanium Grade 5; Ti-6-4 5 R56400 A NR NR 400 1000 407 455 579 614 ASM
Alpha-Beta Ti-6Al-4V Titanium Grade 5; Ti-6-4 5 R56400 A NR NR 455 10 262 317 393 441 559 600 ASM
Alpha-Beta Ti-6Al-4V Titanium Grade 5; Ti-6-4 5 R56400 A NR NR 455 100 124 172 255 303 414 483 ASM
Alpha-Beta Ti-6Al-4V Titanium Grade 5; Ti-6-4 5 R56400 A NR NR 455 1000 124 166 276 366 ASM
Alpha-Beta Ti-6Al-4V Titanium Grade 5; Ti-6-4 5 R56400 STA NR NR 400 10 462 524 586 621 662 703 ASM

From the data you have just downloaded, try to predict the stress at which Ti-11.5Mo-6Zr-4.5Sn will fail at if it needs to last for 750hrs at 370°C. (Yes, you might need to draw a graph).

Draw the graph and explain your answer

In: Mechanical Engineering

During the experiment of shell and tube heat exchanger by using this equipment the Source of...

During the experiment of shell and tube heat exchanger by using this equipment the Source of the water was from the water tap that is mean it is open feed water

To explain more:    the lab engineer used a drink water that supply it from the water tap directly to the heat exchanger equipment

And then he discharge the water to the sink that is not correct way ? I do not have a scientific answer in this but what i think the water from tap is not laminer and the temperature

is not fixed . so I need a real explanation in mechanical and chemical engineering about this

CAN you explain why the way of supplying water like this to the equipment is not good ?

and what the engineer used ?

which type of liquid shall he used ? And why and how it will improve

think about salt in the normal water as well as the bacteria, Think about fouling factor , cleaning heat exchanger regularly,

In: Mechanical Engineering

How does solid solution hardening relate to a phase diagram?

How does solid solution hardening relate to a phase diagram?

In: Mechanical Engineering

I have a 50cc of hydraulic motor, accumulator pressure at 40MPa at max, with 10MPa at...

I have a 50cc of hydraulic motor, accumulator pressure at 40MPa at max, with 10MPa at precharge. How can i determine what pump sizing will i use for hydraulic hybrid purpose.

In: Mechanical Engineering

Describe grain size refinement, solid solution strengthening, precipiation hardening, and work hardening. Why and when do...

Describe grain size refinement, solid solution strengthening, precipiation hardening, and work hardening. Why and when do you use each of these strengthening processes?

In: Mechanical Engineering

Convection heat transfer takes place owing to changes of density within the Fluid. Discusss convective heat...

Convection heat transfer takes place owing to changes of density within the Fluid.

Discusss convective heat transfer in some detail. Your answer should include relavant sketches, equations and practical applications

In: Mechanical Engineering

1. What are the age hardening alloy systems in Al-based alloys based on classification of major...

1. What are the age hardening alloy systems in Al-based alloys based on classification of major alloyingsystems for Al-based alloys?

2.In alloy system of Al - 4.4%Cu - 0.8%Si - 0.8%Mn - 0.5%Mg which is commonly used for aircraft structures, sketch and explain all transformation stages during age hardening. What is the driving mechanism for each step?

In: Mechanical Engineering

Forced convection A thin plate is suspended in air at 1 atm. with T? = 15°C....

Forced convection

A thin plate is suspended in air at 1 atm. with T? = 15°C. Air flows on both sides of the plate where the bottom side absorbs a uniform radiative heat flux of 1542 W/m2. The plate is oriented parallel to the flow and the length along the flow direction is 60 cm. Consider the plate is negligibly thin and the width of the plate (perpendicular to the flow) is large, so that the problem can be considered as a 2D problem.
1. If the temperature of the plate is not to exceed 80°C at any position, what air velocity would be required? Evaluate the air properties at 310 K. (3 pts)
2. Using the velocity calculated in part 1, find an expression for the heat transfer coefficient (h) and surface temperature (Ts) as a function of distance from the leading edge (x). Graph h and Ts for x = 1 ~ 60 cm.
3. If the length of the plate increases to 1.2 m and other conditions (including the air properties) remain the same as in parts 1 and 2, what is the surface temperature at the end of the plate? Graph h and Ts for x = 0.6 ~ 1.2 m

In: Mechanical Engineering

Why do we need methods in addition to tensile testing?

Why do we need methods in addition to tensile testing?

In: Mechanical Engineering

1. Describe how bauxite is converted to aluminium oxide (Al2O3) via the Bayer process? 2. Describe...

1. Describe how bauxite is converted to aluminium oxide (Al2O3) via the Bayer process?

2. Describe the Kroll process used to produce metallic titanium. Give the key chemical equation.

3. Give 2 short application examples of the Ellingham diagram in process metallurgy.

4. Name 2 important fields of application of Ti alloys and an alternative processing route that can provide highest purity Ti.

5. What is the main Al ore and where are the world’s largest reserves? Given the fact that these high alumina containing ore bodies might be depleted in 20-30 years, what could be an alternative source?

6. Describe the electro-refining process of copper and give the most important chemical equations.

In: Mechanical Engineering

6. A motor car, of a total mass 1400 kg, running in top gear at 55...

6. A motor car, of a total mass 1400 kg, running in top gear at 55 km/h, passes on to a rsing gradient of 1 in 20 at that speed. The road and other resistances may be taken as constant at 270 N/t. With condition unchanged, the speed falls uniformly to 40 km/h in a distance of 360 m. An intermediate gear is then engaged for which the speed ratio between the engine and the road wheels is 9:1 and the transmission efficiency is 85 per cent. The engine is then developing a torque of 85 Nm
Determine;
a. The tractive effort before and after the gear change, given that the road wheels are 750 mm diameter, [851 N; 1735 kN]
b. The time between the start of retardation and the recovery of the original speed of 55 km/h and [36 s]
c. The power being developed by the engine when the car is retarding and accelerating through 50 km/h, given that the transmission efficiency in top gear is 94 per cent.         [12.56 kW; 28.35 kW]

In: Mechanical Engineering

4. A wagon of mass 14 tonnes is hauled up an incline of 1 in 20...

4. A wagon of mass 14 tonnes is hauled up an incline of 1 in 20 by a rope which is parallel to the incline and is being wound round a drum of 1 m diameter. The drum, in turn, is driven through a 40 to 1 reduction gear by an electric motor. The frictional resistance to the movement of the wagon is 1.2 kN, and the efficiency of the gear drive is 85 per cent. The bearing friction at the drum and motor shafts may be neglected. The rotating parts of the drum have a mass of 1.25 tonnes with a radius of gyration of 450 mm and the rotating parts on the armature shaft have a mass of 110 kg with a radius of gyration of 125 mm.
At a certain instant the wagon is moving up the slope with a velocity of 1.8 m/s and an acceleration of 0.1 m/s2. Find the torque on the motor shaft and the power being developed. [T= 154 Nm, P=22,24 kW]

In: Mechanical Engineering

A piston with a volume of 0.5 m ^ 3 contains 0.9 kg of water at...

A piston with a volume of 0.5 m ^ 3 contains 0.9 kg of water at a pressure of 0.2 MPa. Heat is transferred to the cylinder until the temperature of the steam at constant pressure is 250 ° C. What happens if the change in kinetic and potential energy is neglected?

A piston with a volume of 0.5 m ^ 3 contains 0.9 kg of water at a pressure of 0.2 MPa. Heat is transferred to the cylinder until the temperature of the steam at constant pressure is 250 ° C. What happens if the change in kinetic and potential energy is neglected?

In: Mechanical Engineering

2. A four-wheeled vehicle has a mass of 1500 kg. the tractive resistance is 1100 N....

2. A four-wheeled vehicle has a mass of 1500 kg. the tractive resistance is 1100 N. The engine develops 60 kW at maximum speed of 2500 r/min. The gear ratio is 45:1 and the transmission efficiency is 87.5%. Each wheel has an effective diameter of 800 mm, a mass of 25 kg and a radius of gyration of 325 m
The parts rotating engine speed have a mass of 70 kg and a radius of gyration of 100 mm.
Determine:
a. The acceleration in m/s2 under these condition [0.7034 m/s2]
b. The maximum speed of the vehicle, in km/h [83,78 km/h]

In: Mechanical Engineering

(a) Calculate the settling velocity of glass spheres (density = 2467 kg/m3) having diameter as 1.5...

(a) Calculate the settling velocity of glass spheres (density = 2467 kg/m3) having diameter as 1.5 mm in water. The slurry contains 65% by weight solid. Use Newton’s law.

(b) Mixture of an ore (density 2000 kg/m3) and gangue (density 7000 kg/m3) is to be separated in a hydraulic elutriator. The mixture has following size distribution, which is valid for ore as well as gangue. Predict the upward velocity of water in elutriator so that entire ore is collected in the overflow. Also ensure that not gangue should be present in overflow. Use fD = 20/Re^0.5 .

In: Mechanical Engineering