In: Math
A new LED light to replace incandescent bulbs has come on the market. The box says it has an average life of 8000 hours with a standard deviation of 200 hours.
A.) What is the probability that a single bulb will last between 7950 and 8100 hours?
B.) What is the probability that the mean of a sample of 75 bulbs picked at random will be between 7950 and 8100 hours?
Solution :
(a)
P(7950 < x < 8100) = P[(7950 - 8000)/ 200) < (x -
) /
<
(8100 - 8000) / 200) ]
= P(-0.25 < z < 0.5)
= P(z < 0.5) - P(z < -0.25)
= 0.2902
(b)
=
/
n = 200 /
75
= P[(7950 - 8000) / 200 /
75 < (
-
)
/
< (8100 - 8000) / 200 /
75)]
= P(2.165 < Z < 4.33)
= P(Z < 4.33) - P(Z < 2.165)
= 0.0152