Question

In: Computer Science

you are givena pair (a,b) .after eatch unit of time pair(a,b) getd changeed to (b-a,b+a).you are...

you are givena pair (a,b) .after eatch unit of time pair(a,b)
getd changeed to (b-a,b+a).you are given the initial value of
pair and an integer n and you have to print the value of the pair at the nth unit of time

Expert Solution

here we consider the time to be starting from t=0

so at t=0 we have

at we have

now following the same pattern and making the first value as

first value = second value - first value

and second value as

second value = second value + first value

we get

at t=2 we have

now following same pattern we have at

t=3

at we have

so from this we can see that at every even position we are getting and at every odd position we are getting

here we take the base case for t=0 and t=1 to be respectively as it is given in question

so final anwer would be the following relation

ans= (a,b) if n=0

(b-a,b+a) if n =1

(n*a, n*b) if(n>0 and n is even)

( (n-1)*(b-a),(n-1)*(b+a)) (if n>1 and n is odd)

venereology answered 2 months ago

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