In: Statistics and Probability
You are given the following hypotheses:
H0: μ = 30
Ha: μ ≠ 30
We know that the sample standard deviation is 10 and the sample
size is 70. For what sample mean would the p-value be equal to
0.05? Assume that all conditions necessary for inference are
satisfied.
The sample mean should be at most or at
least (please round each answer to two decimal
places)
Let X be a random variable and X~N(, ) where ,  both are unknown.
Here, the hypotheses are
H0:=30 against H1:30.
Let be the sample mean corresponding to the sample of size n from X.
Thus, ~N(, /n).
Under H0, the test statistic is, t=√70(-30) /10, which follows t distribution with degrees of freedom (n-2)=68. Since the test is a both tailed test and at 5% level of significance the p value is given as 0.05,
P(l t l t0.025, 68) =0.05
Or, P(l t l1.99) = 0.05[from the distribution table]
Or, P(l (-30)*√70/10 l1.99) =0.05
Or, P[(-30)2.38 or (-30) -2.38]=0.05
Or, P[32.38 or 27.62]=0.05
Thus, the sample mean should be at most 27.62 or at least 32.38 so that the p value be equal to 0.05.