Fire the projectile launcher straight upwards (angle = 90o) at 18 m/s. (Air resistance box should...

Fire the projectile launcher straight upwards (angle = 90^o) at 18 m/s. (Air resistance box should be unchecked, so that air resistance is OFF). Also, the height is at 0m. Using kinematics and showing your work below, determine: A) The time it should take the projectile to reach maximum height. (Hint: Use the kinematic equation v = v₀ – gt) B) The maximum height reached by the projectile.

Expert Solution

The projectile is projected vertically upwards. The acceleration on the particle is the acceleration due to gravity, g which is acting in the opposite direction of the particle, so the particle's velocity will decrease with time and after a certain height it will stop and returns.

At maximum height the velocity of the particle will be 0m/s and after that the particle start moving in opposite direction.

Therefore from Newton's equation

V = V₀ - gt, here acceleration is negative since it is acting downward while the particle is moving up, V is the velocity of the particle at maximum height and v=0, also V₀ is the initial velocity of the particle when it was launched.

Therefore 0 = 18 - 9.8t

t = 18/9.8

t = 1.84 s . This is the time taken fir the particle to reach maximum height.

Now the maximum height can be found out using the equation

V² - V_o² = - 2gs

0 - 18² = -2*9.8*s

324 = 19.6*s

S = 324/19.6

S = 16.53 m is the maximum height attained by the particle.

genius_generous answered 2 years ago

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