In: Physics
A projectile is fired at ?0=394.0 m/s at an angle of ?=68.1∘ , with respect to the horizontal. Assume that air friction will shorten the range by 34.1% . How far will the projectile travel in the horizontal direction, ? ?
Speed v = 394 m / s
Angle θ = 68.1 degree
Range when air friction is negligiable R = v^2 sin 2θ / g
=394^2*sin(2*68.1)/9.8
= 10961.56 m
Range due to air friction R ' = R - 34.1 % of R
= R - 0.341 R = 0.659*R
= 0.659*10961.56
R' = 7223.66 m