A projectile is fired at ?0=394.0 m/s at an angle of ?=68.1∘ , with respect to...

A projectile is fired at ?0=394.0 m/s at an angle of ?=68.1∘ , with respect to the horizontal. Assume that air friction will shorten the range by 34.1% . How far will the projectile travel in the horizontal direction, ? ?

Solutions

Expert Solution

Speed v = 394 m / s
Angle θ = 68.1 degree
Range when air friction is negligiable R = v^2 sin 2θ / g =394^2*sin(2*68.1)/9.8
                                                           = 10961.56 m
Range due to air friction R ' = R - 34.1 % of R
                                          = R - 0.341 R = 0.659*R
                                          = 0.659*10961.56
                                  R' = 7223.66 m

genius_generous answered 1 month ago

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