A projectile is launched with an initial speed of 60 m/s at an angle of 35°...

A projectile is launched with an initial speed of 60 m/s at an angle of 35° above the horizontal. The projectile lands on a hillside 4.0 s later. Neglect air friction. (a) What is the projectile's velocity at the highest point of its trajectory? m/s (b) What is the straight-line distance from where the projectile was launched to where it hits its target? m

Solutions

Expert Solution

At highest point, only horizontal velocity is there ie. 49.15m/s.

To calculate the straight line distance from start to final point we find total distance traveled in horizontal and vertical directions.

In horizontal direction velocity is constant, but in verticle direction object has gravitational acceleration.

The object takes 3.5s to reach top point. And after that it comes back downward in remaining time. So we find the difference of maximum height and distance travelled in 0.5s and that will be vertical displacement.

genius_generous answered 1 year ago

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