In: Statistics and Probability
Use MS Excel to answer this. From the data given below test a hypothesis for variances being equal. Use α = 0.05.
| Section A | Section B |
| 15 | 16 |
| 26 | 52 |
| 52 | 55 |
| 53 | 57.5 |
| 54 | 58 |
| 56.5 | 60 |
| 61 | 61 |
| 61.5 | 70 |
| 63 | 70 |
| 66 | 71 |
| 66 | 72 |
| 66.5 | 73 |
| 69 | 74.5 |
| 71 | 75 |
| 77 | 75.5 |
| 77 | 76 |
| 78 | 77 |
| 79 | 81 |
| 81 | 85 |
| 86 | 85.5 |
| 87 | 86 |
| 90 | 88 |
| 90 | 88.5 |
| 91 | 91 |
| 91 | 93 |
| 94 | |
| 95 | |
| 96 | |
| 98 | |
| 98 | |
| 99.5 | |
| 100 |
as instructed,i am using excel to solve the problem .
steps:-
copy the data in excel including the labels
data analysis
F test two sample for variances
ok
in variable 1 range select the range of section A including label
and in variable 2 range select the range of section B
including label
tick labels
in alpha type 0.05
in output range select any blank cell of excel sheet
ok.
your output be:-
| F-Test Two-Sample for Variances | ||
| Section A | Section B | |
| Mean | 68.3 | 77.25 |
| Variance | 365.8125 | 326.8548 |
| Observations | 25 | 32 |
| df | 24 | 31 |
| F | 1.119189 | |
| P(F<=f) one-tail | 0.379346 | |
| F Critical one-tail | 1.875073 | |
solution to our problem:-
hypothesis:-


as we have to test a hypothesis for variances being equal. i have used the two sided alternative hypothesis .
test statistic(F) = 1.119
p value = 2 * p
value for one tail = (2*0.379346)
0.7587
decision:-
p value = 0.7587 > 0.05 (alpha)
so, we fail to reject the null hypothesis.
conclusion:-
there is sufficient evidence to claim that variances are equal at α = 0.05.
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