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Three forces are applied to an object, as shown in the figure. F1 Baseline has a...

Three forces are applied to an object, as shown in the figure. F1 Baseline has a magnitude of 24.0 newtons (24.0 N) and is directed 30.0° to the left of the +y axis. F2 has a magnitude of 14.9 N and points along the +x axis. What must be the (a) magnitude and (b) direction (specified by the angle theta in the drawing) of the third force F3 such that the vector sum of the three forces is 0 N?

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Three forces are applied to an object, as shown in the figure.Force F1 has a magnitude of 23.4 newtons (N) and is directed 30.0degrees to the left of the + y axis. Force F2 has a magnitude of13.1 N and points along the + x axis. A third force F3 is appliedsuch that the vector sum of the three forces is 0 N. What are (a)the magnitude and (b) direction of this third force F3? Specify thedirection as a positive angle relative to the negative x axis, asshown in the figure.

Sum the y-components of F1 and F2:

Fy =F1cos30           [F2 has no y-components...]

Fy = 20.265 N

Sum the x-components:

Fx = -F1sin30 + F2

Fx = 1.4 N

The third force is cancelling out those components, so:

F3y = - 20.265 N

F3x = -1.4 N

F3 = ?(20.2652 + 1.42)

F3 = 20.31 N

tan? = F3y/F3x = -20.265 /-1.4

? = 86.0 degrees

F3 = 20.31 N @86.0o

genius_generous answered 3 months ago
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