Question

In: Physics

A small object is 25.0 cm from a diverging lens as shown in the figure. A...

A small object is 25.0 cm from a diverging lens as shown in the figure. A converging lens with a focal length of 12.0 cm is
30.0 cm to the right of the diverging lens. The two-lens system forms a real inverted image 17.0 cm to the right of the
converging lens. What is the focal length of the diverging lens? What is the total magnification of the final image?

Solutions

Expert Solution

Focal length of diverging lens is

Focal length of converging lens is

Distance between two lenses

For the first lens(diverging lens): Object distance from diverging lens

Thin lens formula ( real positive sign convention)

--------(1)

For the second lens ( converging lens) , Object distance from converging lens

Focal length of converging lens

Final image is formed at to the right of converging lens.

Thin lens formula ( real positive sign convention)

Using above value in equation (1)

Focal length of diverging lens is (negative sign indicates the lens is a diverging lens)

Magnification ( )

(negative sign indicates the final image is inverted)

Focal length of diverging lens is and Magnification of final image is .


Related Solutions

A 1.8-cm-tall object is 3.1 cm to the left of a diverging lens with a focal...
A 1.8-cm-tall object is 3.1 cm to the left of a diverging lens with a focal length of -3.1 cm. A converging lens with a focal length of 4.6 cm is distance d to the right of the first lens. a) For what value of d is the image at infinity? b) What is the angular size of the image as seen by looking through the converging lens? ?c) What is the angular magnification of this two-lens magnifier?
An object is placed 22.7 cm to the left of a diverging lens (f = -13.0...
An object is placed 22.7 cm to the left of a diverging lens (f = -13.0 cm). A concave mirror (f = 9.99 cm) is placed 29.9 cm to the right of the lens to form an image of the first image formed by the lens. Find the final image distance, measured relative to the mirror. (b) Is the final image real or virtual? (c) Is the final image upright or inverted with respect to the original object?
An object is placed 12 cm in front of a diverging lens with a focal length...
An object is placed 12 cm in front of a diverging lens with a focal length of 7.9 cm. (a) Find the image distance and determine whether the image is real or virtual. (b) Find the magnification
An object is placed 27.2 cm to the left of a diverging lens (f = -10.6...
An object is placed 27.2 cm to the left of a diverging lens (f = -10.6 cm). A concave mirror (f = 17.1 cm) is placed 40.3 cm to the right of the lens to form an image of the first image formed by the lens. Find the final image distance, measured relative to the mirror. (b) Is the final image real or virtual? (c) Is the final image upright or inverted with respect to the original object?
Problem 1) A 5 cm tall object is 20 cm in front of a diverging lens...
Problem 1) A 5 cm tall object is 20 cm in front of a diverging lens with a focal length of 10 cm. a) What is the location of the image? -6.67cm b) What is the height of the image? -1.67 cm c) The image is:virtual d) The image is:upright At 15 cm to the right of the lens in problem 1 we add a converging lens with a focal length of 10 cm. a) What is the location of...
The distance between an object and its image formed by a diverging lens is 51.7 cm....
The distance between an object and its image formed by a diverging lens is 51.7 cm. The focal length of the lens is -235 cm. a.) Find the image distance b.) Find the object distance.
The distance between an object and its image formed by a diverging lens is 8.20 cm....
The distance between an object and its image formed by a diverging lens is 8.20 cm. The focal length of the lens is -3.70 cm. Find (a) the image distance and (b) the object distance.
A diverging lens of focal length -12.5 cm is placed 40.0 cm from a converging lens...
A diverging lens of focal length -12.5 cm is placed 40.0 cm from a converging lens of unknown focal length.  A 15.2 cm tall erect object is placed 25.3 cm in front of the diverging lens which is to produce an image on a screen that is twice the size of the original object but inverted. A) Where should the screen be located to produce a clear image? Give the distance from the converging lens to the screen in cm. B)...
A diverging lens of focal length 15 cm forms an image of object placed at 30...
A diverging lens of focal length 15 cm forms an image of object placed at 30 cm from the lens. The magnification of the lens is:
A 6·cm tall candle is placed 200·cm from a diverging lens with a focal length of...
A 6·cm tall candle is placed 200·cm from a diverging lens with a focal length of 50·cm. Note: enter the absolute value of your answers for all distances and heights ... use the signs to determine the type and orientation of the images. (a) How far from the lens will the image be? cm. (b) How tall will the image be? Now, imagine that the candle is moved closer, so that it is only 20·cm from the lens. (d) How...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT