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Consider a locus with two alleles - B and b. B is dominant, while b is...

Consider a locus with two alleles - B and b. B is dominant, while b is recessive. There is no mutation. B has a selective advantage relative to b, so that the fitnesses of the three genotypes are BB = 1, Bb = 1, and bb = 1-s. In this case, s = 0.50, so that bb homozygotes have 50% fitness of heterozygotes and BB homozygotes. If the population has the following genotypic counts prior to selection of BB = 500, Bb = 250, and bb = 250, what is the expected change in the frequency of B after one generation with selection? Please give your answer to two decimal places.

Solutions

Expert Solution

Given :

Fitnesses of the three genotypes are WBB = 1, WBb = 1, and Wbb = 0.5.

Genotypic counts prior to selection of BB = 500, Bb = 250, and bb = 250.

Total number of individuals= (500+250+250)

= 1000

Thus, total number of alleles = 2×1000

=2000

Allele frequency of B before selection,

= Total number of B alleles/ Total alleles in population

Number of B alleles =( 2 × BB types) + ( 1 × Bb types)

Thus, frequency of allele B will become 0.67 after selection.

Change in frequency= 0.67 - 0.625

=~0.05

gladiator answered 2 months ago
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