Question

C question

Using a for-loop: (a) calculate the length of a string, (b) find a word in a string

Answer 1

C CODE FOR PART (a) AND PART (b):

#include <stdio.h>

// (a) Function to return length of string using a for loop

int length(char str[]){

    int count = 0;

    for(int i = 0; str[i] != '\0'; i++)

        count++;

    return count;

}

// (b) Function to check if word is present in string using for loop

// Return 1 if word is present otherwise 0

int find(char str[], char word[]){

    int strLength = length(str); // Find length of string

    int wordLength = length(word); // Find length of word

    int isFound = 1;

    for(int i = 0; i < strLength - wordLength; i++){

        isFound = 1;

        for(int j = 0; j < wordLength; j++){

            if(str[i + j] != word[j]){    

                isFound = 0;

                break;

            }

        }

        if(isFound)

            return 1;

    }

    return 0;

}

int main(){

    char str[] = "I love programming in C";

    char word1[] = "programming";

    char word2[] = "C++";

    printf("Length of string \"%s\" is %d\n", str, length(str));

    if(find(str, word1))

        printf("\"%s\" found in string\n", word1);

    else

        printf("\"%s\" NOT found in string\n", word1);

    if(find(str, word2))

        printf("\"%s\" found in string\n", word2);

    else

        printf("\"%s\" NOT found in string\n", word2);

    return 0;

}

OUTPUT:

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