In: Math
SupposeSuppose the heights of 18-year-old men are approximately normally distributed, with mean 66 inches and standard deviation 1 inches.
(a) What is the probability that an 18-year-old man selected at
random is between 65 and 67 inches tall? (Round your answer to four
decimal places.)
(b) If a random sample of nine 18-year-old men is
selected, what is the probability that the mean height x
is between 65 and 67 inches? (Round your answer to four decimal
places.)
(c) Compare your answers to parts (a) and (b). Is the probability
in part (b) much higher? Why would you expect this?
The probability in part (b) is much higher because the standard deviation is smaller for the x distribution.
The probability in part (b) is much higher because the standard deviation is larger for the x distribution.
The probability in part (b) is much higher because the mean is smaller for the x distribution.
The probability in part (b) is much higher because the mean is larger for the x distribution.
The probability in part (b) is much lower because the standard deviation is smaller for the x distribution.
(a) What is the probability that an 18-year-old man selected at
random is between 65 and 67 inches tall? (Round your answer to four
decimal places.)
P(65<X<67)
mean=66 sd=1
using R software nad pnorm function we get the probability
pnorm(67,mean=66,sd=1)-pnorm(65,mean=66,sd=1)
Output:
0.6826895
ANSWER:0.6827
(b) If a random sample of nine 18-year-old men
is selected, what is the probability that the mean height x is
between 65 and 67 inches? (Round your answer to four decimal
places.)
sample stddev=popsd/sqrt(n)
=1/sqrt(9)
=1/3
=0.333333
P(67<xbar<65)
use below R code:
pnorm(67,mean=66,sd=0.333333333)-pnorm(65,mean=66,sd=0.333333333)
output;
0.9973002
ANSWER:0.9973
c) Compare your answers to parts (a) and (b). Is the probability in part (b) much higher? Why would you expect this?
yes higher
The probability in part (b) is much higher because the standard deviation is smaller for the xdistribution.