In: Biology
You are studying a population of wild turtles on a remote Pacific island. You have been following the allelic frequencies at a single two-allele locus 'S', which controls embryonic survival through simple Mendelian inheritance with dominance. The population has been in Hardy-Weinberg equilibrium at this locus for many generations.
At Hardy-Weinberg equilibrium, the frequency of the recessive allele Sd is 0.88
The genotypic frequencies at Hardy-Weinberg equilibrium are as follows:
f(SDSD) = 0.0144
f(SDSd) = 0.2112
f(SdSd) = 0.7744
An increase in ocean temperature between 2018 and 2019 is thought to have driven the population away from Hardy-Weinberg equilibrium at the S locus.
The numbers of sampled offspring by genotype after the 2019 hatch are as follows:
SDSD : 200
SDSd : 200
SdSd : 40
Calculate the relative fitness (W) values for each genotype (you will need all these values in a subsequent step).
a) The relative fitness value for the SdSd genotype is [A] (enter your answer as a decimal in the form '0.x'; do not spell out the number as a word; there are no units to include)
b) The type or form of natural selection that has occurred is [B] (use the specific phrase that describes this form of selection completely!).
Now, calculate all genotypic frequencies in the 2019 offspring (first generation after selection):
c) post-selection f(SDSD) = [C] (perform this and the following two calculations (d and e) to four significant figures after the decimal point; enter your answers in the exact form '0.wxyz'; make sure to round off correctly; there are no units)
d) post-selection f(SDSd) = [D]
e) post-selection f(SdSd) = [E]
f) The frequency of the Sd recessive allele in the 2019 offspring (first generation after selection) is [F] (perform the calculation with four significant figures, then round off to 2 significant figures in the final answer; enter your answer in the exact form '0.xy')
The population of wild turtles are in Hardy Weinberg equilibrium
and the allele S controls the embryonic survival through simple
Mendelian inheritance with dominance. The frequency of recessive
allele Sd,
therefore, the frequency of dominant allele, SD,
, the given genotype frequencies are as follows:
f(SDSD)= p2= 0.0144;
f(SDSd), 2pq=0.2112;
f(SdSd), q2=0.7744
The number of sampled offspring by genotype after the 2019 hatch are as follows: SDSD=200; SDSd=200; SdSd=40
Therefore, the relative fitness for the
SDSD genotype,
; relative fitness for the SDSd genotype,
; relative fitness for the SdSd genotype,
(a) The relative fitness value for the SdSd genotype =0.2.
(b) Here, wDD=wDd=1 and wdd<1. The heterozygote alomg with the homozygous dominant has the highest fitness, which is greater than that of the homozygous recessive. Natural selection is operating against the recessive allele, Sd.
The mean fitness,
(c) Post selection f(SDSD)=
(d) Post selection f(SDSd)=
(e) Post selection f(SdSd)=
(f) Frequency of allele SD after selection,
; therefore the frequency of the Sd allele after
selection,
.