In: Physics
An opaque cylindrical tank with an open top has a diameter of 2.80 m and is completely filled with water. When the afternoon Sun reaches an angle of 31.2
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an opaque cylindrical tank with an open top has a diameter of3.00 m and is completely filled with water. when theafternoon Sun reaches an angle of 28.0 degrees above the horizon,sunlight ceases to illuminate any part of the bottom of thetank. how deep is the tank?
When light passes from one medium to another it bends due torefraction.
So your question can be picturised as follows,
when the afternoon Sun reaches an angle of 28.0 degrees abovethe horizon, sunlight ceases to illuminate any part of the bottomof the tank , the bottom will remain dark
Here i is the angle of incidence and r is the angle ofrefraction.
i =90-28 =62 degrees.
Now we can apply snells law,
n1sin i = n2sin r . {n1=1isthe refractive index of air and n2=1.33 is that ofwater
sin r =sin 62/1.33 =0.66. or r=sin-10.66