Question

Write a loop that sets newScores to oldScores shifted once left, with element 0 copied to the end. Ex: If oldScores = {10, 20, 30, 40}, then newScores = {20, 30, 40, 10}.

--------------Code Below-----------

#include <iostream>
using namespace std;

int main() {
const int SCORES_SIZE = 4;
int oldScores[SCORES_SIZE];
int newScores[SCORES_SIZE];
int i;

for (i = 0; i < SCORES_SIZE; ++i) {
cin >> oldScores[i];
}

/* Your solution goes here */

for (i = 0; i < SCORES_SIZE; ++i) {
cout << newScores[i] << " ";
}
cout << endl;

return 0;
}

Answer 1

#include <iostream>
using namespace std;

int main() {
const int SCORES_SIZE = 4;
int oldScores[SCORES_SIZE];
int newScores[SCORES_SIZE];
int i,j;

for (i = 0; i < SCORES_SIZE; ++i) {
cin >> oldScores[i];
}
//  oldScores with element 0 copied to the end of newScores.
newScores[SCORES_SIZE-1]=oldScores[0];

//a loop that sets newScores to oldScores shifted once left
for(j=1;j<SCORES_SIZE;j++){
    newScores[j-1]=oldScores[j];
}

//result
for (i = 0; i < SCORES_SIZE; ++i) {
cout << newScores[i] << " ";
}
cout << endl;

return 0;
}

//screenshot of the code

output:

Explanation:

• First we are assigning the 0th position of oldscore to the end position of a new score.
• Next we are going to write a for loop that starts with 1 position to size of score and shifting left elements to newscore
• eg when j=1 ,oldscore [1] =20 is assigned to newscore[j-1] i.e newscore[0] =20 similarly all the elements are shifted left
• Later we printing the result of newscore