A soda ("7up") maker conducted a survey in 3 schools to see if children liked their...

A soda ("7up") maker conducted a survey in 3 schools to see if children liked their brand over another generic soda. The Results are in table below...

School	7 up	Generic brand
School 1	232	168
School 2	260	240
School 3	197	203

Using a 5% significance level and based on the sample data above find out if the children liked the "7 up" over the generic kind.

Solutions

Expert Solution

H0: Null Hypothesis: ( the children did not like the "7 up" over the generic kind.)

HA: Alternative Hypothesis: ( the children liked the "7 up" over the generic kind.) (Claim)

From the given data, the following statistics are calculated:

n1 = 3

1 = 689/3 = 229.6667

s1= 31.5647

n2 = 3

2 = 611/3 = 203.6667

s2 = 36.0046

Pooled Standard Deviation is given by:

Test Statistic is given by:

df = 3 + 3 - 2 = 4

= 0.05

From Table, critical value of t = 2.132

Since calculated value of t is less than critical value of t, the difference is not significant. Fail to reject null hypothesis.

Conclusion:
The data do not support the claim that the children liked the "7 up" over the generic kind.

orchestra answered 1 year ago

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