In: Statistics and Probability
A soda ("7up") maker conducted a survey in 3 schools to see if children liked their brand over another generic soda. The Results are in table below...
School | 7 up | Generic brand |
School 1 | 232 | 168 |
School 2 | 260 | 240 |
School 3 | 197 | 203 |
Using a 5% significance level and based on the sample data above find out if the children liked the "7 up" over the generic kind.
H0: Null Hypothesis: ( the children did not like the "7 up" over the generic kind.)
HA: Alternative Hypothesis: ( the children liked the "7 up" over the generic kind.) (Claim)
From the given data, the following statistics are calculated:
n1 = 3
1 = 689/3 = 229.6667
s1= 31.5647
n2 = 3
2 = 611/3 = 203.6667
s2 = 36.0046
Pooled Standard Deviation is given by:
Test Statistic is given by:
df = 3 + 3 - 2 = 4
= 0.05
From Table, critical value of t = 2.132
Since calculated value of t is less than critical value of t, the difference is not significant. Fail to reject null hypothesis.
Conclusion:
The data do not support the claim that the children liked the "7
up" over the generic kind.