In: Operations Management
Problem 2: Number of defective tires produced in 20 batches of 100 units each is given below.
2, 5, 7, 1, 3, 5, 9, 12, 16, 5, 9, 12, 2, 14, 4, 7, 6, 8, 9, 11
What control charts will be appropriate? Develop upper and lower control limits for such charts. The next batch of 100 units showed 12 defectives. Is the process in control?
Problem 3: Inspection of 12 car panels in a Mercury plant showed the following number of defects on each panel:
9, 4, 3, 17, 24, 12, 10, 25, 12, 34, 10, 10
What control charts will be appropriate? Develop upper and lower control limits for such charts. Suppose the next three panels showed no defect at all. Is this process out of control? Why or why not?
1. P-CHART WOULD BE APPROPRIATE HERE.
Z = 3
SAMPLE SIZE = 100
NUMBER OF SAMPLES TAKEN = 20
P-BAR = TOTAL NUMBER OF DEFECTS / (SAMPLE SIZE * NUMBER OF
SAMPLES = 147 / (100 * 20) = 0.0735
STDEV = SQRT((PBAR * (1 - PBAR)) / SAMPLE SIZE = SQRT((0.0735 * (1
- 0.0735)) / 100 = 0.0261
UCL = PBAR + (Z * STDEV) = 0.0735 + (3 * 0.0261) = 0.1518
LCL = PBAR - (Z * STDEV) = 0.0735 - (3 * 0.0261) = -0.0048, SINCE
LCL IS NEGATIVE, LCL = 0
2. NO, SINCE 1 POINT IS OUTSIDE THE CONTROL LIMIT(OBSERVATION 9), THE PROCESS IS NOT IN STATISTICAL CONTROL.
2. C CHART IS APPROPRIATE HERE
Z = 3
TOTAL NUMBER OF DEFECTS = 170
NUMBER OF SAMPLES = 12
C-BAR = TOTAL NUMBER OF OBSERVATIONS / NUMBER OF SAMPLES = 170 / 12 = 14.1667
UCL = C-BAR + (Z * SQRT(C-BAR)) = 14.1667 + (3 * SQRT(14.1667))
= 25.46
LCL = C-BAR - (Z * SQRT(C-BAR)) = 14.1667 - (3 * SQRT(14.1667)) =
2.88
2. THE CHART IS OUT OF CONTROL BECAUSE OBSERVATION 10 IS OUTSIDE
THE CONTROL LIMITS.
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