Question

In: Chemistry

1.)What is the pressure (in millimeters of mercury) inside a container of a gas connected to...

1.)What is the pressure (in millimeters of mercury) inside a container of a gas connected to an open-end manometer when the level in the arm connected to the container is 344.5 mm in height lower than the level in the arm open to the atmosphere? Atmospheric pressure is 765.1 mm Hg and the density of mercury is 13.546 g/mL.

2.)What is the pressure (in millimeters of mercury) inside a container of a gas connected to an open-end manometer filled with CHCl2Br (density = 2.451 g/cm3) when the level in the arm connected to the container is 898.4 mm in height higher than the level in the arm open to the atmosphere? Atmospheric pressure is 755.1 mm Hg and the density of mercury is 13.546 g/mL.

3.)Two separate flasks are each filled with a gas at 25.0°C; the valve between them is opened and the gases are allowed to mix. What would be the final pressure in atmospheres after mixing, if initially C2H2 is in the first flask (Volume = 3.000 L) at 313.6 torr and Kr is in the second flask (Volume = 2.000 L) at 222.6 torr?

Solutions

Expert Solution

1) From the given data, Pgas > Patm height of liquid = (765.1+344.5) mmHg = 420.6 mmHg

The actual pressure of mercury, P = p*g*h

                                                          = (0.013546 kg/10-6 m3)(9.1 m/s2 )(1.1096 m) = 1.36*105 Pa =1033.6 mmHg

2) Patm > Pgas, therefore height of manometer = 898.4 - 755.1= 143.3 mmHg

The actual pressure of mercury, P = p*g*h

                                                          = (0.013546 kg/10-6 m3)(9.1 m/s2 )(0.1433 m) = 134.2 mmHg

3) Resultant pressure =


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