Question

Use a switch statement on a char variable to write a function that's a simple calculator that keeps running waiting for input

Should have a do while loop that continually loops the function, prompting for a new input and new operator, until the calculator returns 0, in which case it will close.

Answer 1

As the programming language is not mentioned, it is done C language

Source Code:

#include<stdio.h> // header file for input output functions
main() { // main function
   int s,total; // declaring required variables
   char cha;
   do{ // do while starting
       printf(" Enter a number: "); // asking for a number
       scanf("%d",&s); // storing it into s every time
       printf(" Enter a operator(+,-,*,/): "); // asking for a operator
       scanf(" %c",&cha); // stroring into cha variable
       switch(cha){ // switch statement testing the operator
           case '+': total+=s; // if operator is + then add s to previous total
           break;
           case '-': total-=s; // if - substract sfrom total
           break;
           case '*': total*=s; // if * multiply s with total
           break;
           case '/': total/=s;// if / divide s by total
           break;
           default: printf(" Enter a valid operator!!");
       }
       printf(" Total is: %d ",total); // priting the total in each round
   }while(total!=0); // until total becomes 0
}// end of main

OUTPUT:

The below image is the output of the above code. It is run until the value becomes 0.