Question

If the DCP solution is 0.01278M and you need 23.93 mLs of the DCP solution to completely react with the ascorbic acid, how many grams of ascorbic acid are in your sample? Do not write the answer in scientific notation. Make sure you use the correct number of significant figures and the correct units.

Answer 1

Solution :-

Lets first calculate the moles of the DCP using its molarity and volume ?

moles = molarity * volume in liter

moles of DCP = 0.01278 mol per L * 0.02393 L                     (23.93 ml = 0.02393 L)

                    = 0.000306 mol DCP

now lets calculate the moles of Ascorbic acid

0.000306 mol DCP * 1 mol Ascorbic acid / 1 mol DCP = 0.000306 mol Ascorbic acid

now lets convert moles of ascorbic acid to its mass

mass = moles * molar mass

molar mass of ascorbic acid = 176.12 g per mol

mass of ascorbic acid = 0.000306 mol * 176.12 g per mol

                                 = 0.05386 g Ascorbic acid.

Therefore the mass of the ascorbic acid in the sample is 0.05386 g