Question

Having a problem with syntax error in Java:

JAVA (Perfect Numbers) An integer number is said to be a perfect number if its factors, including 1 (but not the number itself), sum to the number. For example, 6 is a perfect number, because 6 = 1 + 2 + 3. Write a method isPerfect that determines whether  parameter number is a perfect number. Use this method in an application that displays all the perfect numbers between 1 and and integer entered by the user. Display the factors of each perfect number to confirm that the number is indeed perfect. Challenge the computing power of your computer by testing numbers much larger than 1000. Display the results.

import java.util.Scanner;
public class IsPerfect {
   static boolean isPerfect(int n)
   { int Sum = 0;
   for (int i=1; i<n ; i++) {
       if(n% i == 0) {
           Sum = Sum + i;
       }
   }
  
   if (Sum == n) {
       return true;
   }
  
   else {
       return false;
   }
}

   public static void main(String[] args) {
   int user_input; // taking user input
   try (Scanner input = new Scanner(System.in)){
  
   System.out.println("Perfect numbers between 1 and "+ user_input + "are:");
   for (int i=1; i<= user_input; i++){
if (isPerfect(i)){
   System.out.println(i);

}
       }
   }
  
}

Answer 1

Answer:

Here is the corrected java code as per your requirement

Raw code:

import java.util.Scanner;

//class named IsPerfect

public class IsPerfect {

//static method to verify weather Perfect number of not

static boolean isPerfect(int n)

//declaring sum value

{

int Sum = 0;

//for loop over the value time

for (int i=1; i<n ; i++) {

//checking if the value leaves reminds 0 multiplied with i

if(n% i == 0) {

//if yes increment sum

Sum = Sum + i;

}

}

//if sum is same value

if (Sum == n) {

//return true it as IsPerfect number

return true;

}

//else no

else {

return false;

}

}

//main method

public static void main(String[] args) {

//declaring varialble

int user_input;

// taking user input

Scanner input = new Scanner(System.in);

//getting integer

user_input=input.nextInt();

//print on the console

System.out.println("Perfect numbers between 1 and "+ user_input + "are:");

//iterate over the values from 1 to user_input range

for (int i=1; i<= user_input; i++){

//check every value if its Perfect number

if (isPerfect(i)){

//if it is print the valu

System.out.println(i);

}

}

}

}

Editor:

output:

Hope this helps you! If you still have any doubts or queries please feel free to comment in the comment section.

"Please refer to the screenshot of the code to understand the indentation of the code".

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