Question

In: Chemistry

Part A:You are using a Geiger counter to measure the activity of a radioactive substance over...

Part A:You are using a Geiger counter to measure the activity of a radioactive substance over the course of several minutes. If the reading of 400. counts has diminished to 100. counts after 61.7 minutes , what is the half-life of this substance?

Part B; An unknown radioactive substance has a half-life of 3.20 hours . If 27.1 g of the substance is currently present, what mass A0 was present 8.00 hours ago?

Part C:Americium-241 is used in some smoke detectors. It is an alpha emitter with a half-life of 432 years. How long will it take in years for 37.0 % of an Am-241 sample to decay?

PART D;A fossil was analyzed and determined to have a carbon-14 level that is 20 % that of living organisms. The half-life of C-14 is 5730 years. How old is the fossil?

Solutions

Expert Solution

Part A

400 counts dropping to 100 counts means two half lives have passed

400 --> 200 one half life
200 --> 100 one half life

so the half life is 61.7/2 =30.85 mins

Part B

Use this equation below to find out how much of a radioactive material is left after a given period of time. You can use the equation in reverse to find out the initial
mass of the radioactive material if you know its current mass.

A = current mass of radioactive material = 27.1 g
A0 = initial mass of radioactive material = to be determined
T½ = half-life of the radioactive material = 3.20 h
t = elapsed time since the original mass was present = 8.00 h

A = A0e^(-0.693t/T½)
A/A0 = e^(-0.693t/T½)
ln (A/A0) = ln [e^(-0.693t/T½)]
ln A - ln A0 = (-0.693t/T½)
ln A = -0.693t/T½ + ln A0

ln 27.1 = -0.693(8.00 h)/3.20 h + ln A0

3.211 = -1.7325 + ln A0

3.211  + 1.7325 = ln A0

ln A0 = 3.211 + 1.7325

ln A0 =4.9435

A0 = e^4.9435

A0 = 140.26  Initial Mass of Radioactive Material

Part C:

t1/2 = 0.693/K

K = 0.693 / 432

K = 1.6042 * 10^-3

K = 2.303/t log(a / (a-x))

1.6042 * 10^-3 = 2.303 / t log (100/(100-37))

t = 71.74 years.

Part D:

Let the amount (No) of carbon sample be 100g

So the amount left (Nt) = 20% of 100g = 20g

Using the formula ,

Nt = No (1/2)t / t 0.5

where t is the amount of time lapsed

and t 0.5 is the half life period

putting all the values we get ,

20 = 100 (1/2)t / 5730

t = 13304.65 years

So the fossil must be 13304.65 years old.


Related Solutions

You are using a Geiger counter to measure the activity of a radioactive substance over the...
You are using a Geiger counter to measure the activity of a radioactive substance over the course of several minutes. If the reading of 400. counts has diminished to 100. counts after 63.7 minutes , what is the half-life of this substance?
Part A: You are using a Geiger counter to measure the activity of a radioactive substance...
Part A: You are using a Geiger counter to measure the activity of a radioactive substance over the course of several minutes. If the reading of 400. counts has diminished to 100. counts after 28.1 minutes, what is the half-life of this substance? Part B: An unknown radioactive substance has a half-life of 3.20 hours. If 15.7 g of the substance is currently present, what mass A0 was present 8.00 hours ago? Part C: Americium-241 is used in some smoke...
Part A You are using a Geiger counter to measure the activity of a radioactive substance...
Part A You are using a Geiger counter to measure the activity of a radioactive substance over the course of several minutes. If the reading of 400. counts has diminished to 100. counts after 26.3 minutes , what is the half-life of this substance? Part B An unknown radioactive substance has a half-life of 3.20 hours . If 10.6 g of the substance is currently present, what mass A0 was present 8.00 hours ago?
11) Part A You are using a Geiger counter to measure the activity of a radioactive...
11) Part A You are using a Geiger counter to measure the activity of a radioactive substance over the course of several minutes. If the reading of 400. counts has diminished to 100. counts after 70.8 minutes , what is the half-life of this substance? Express your answer with the appropriate units. t1/2 = Part B An unknown radioactive substance has a half-life of 3.20 hours . If 24.2 gof the substance is currently present, what mass A0 was present...
A Geiger counter counts the number of alpha particles from radioactive material. Over a long period...
A Geiger counter counts the number of alpha particles from radioactive material. Over a long period of time, an average of 25 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period. Round your answer to four decimals.     Find the probability that at least two particles arrive in a particular 2 second period. Round your answer to four...
Part A 1.How does a Geiger-Muller counter detect radioactivity? Match the words in the left column...
Part A 1.How does a Geiger-Muller counter detect radioactivity? Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer. Help Reset passing through conduct electricity counting detecting instant argon gas liquid electrodes collide with neon gas ionize The Geiger-Muller counter is an------method of -----radioactivity that is based on the radioactive particle---- a chamber of----. The radioactive particles-----part of the-----, which can then----across -----...
In a Geiger counter, a thin metallic wire at the center of a metallic tube is...
In a Geiger counter, a thin metallic wire at the center of a metallic tube is kept at a high voltage with respect to the metal tube. Ionizing radiation entering the tube knocks electrons off gas molecules or sides of the tube that then accelerate towards the center wire, knocking off even more electrons. This process eventually leads to an avalanche that is detectable as a current. A particular Geiger counter has a tube of radius R and the inner...
1) A radioactive substance decays at a rate proportional to the amount of the substance at...
1) A radioactive substance decays at a rate proportional to the amount of the substance at present time. Initially 200 grams of a the substance was present and remain 80% of the initial amount after 2 hours. A.) Determine the amount of the substance remaining after 10 hours (counted in grams) B.) Determine the time that 60% of the initial amount of the substance has decayed (counted in hours)
The activity of a sample of radioactive material was measured over 12 h. The following net...
The activity of a sample of radioactive material was measured over 12 h. The following net count rates were obtained at the times indicated: Time (h) Counting Rate (counts/min) 1 3100 2 2450 4 1480 6 910 8 545 10 330 12 200 1a) Plot the activity curve on semilog paper. 1b) Determine the disintegration constant and the half-life of the radioactive nuclei in the sample.
The activity of a sample of radioactive material was measured over 12 h. The following net...
The activity of a sample of radioactive material was measured over 12 h. The following net count rates were obtained at the times indicated: Time (h) Counting Rate (counts/min) 1 3100 2 2450 4 1480 6 910 8 545 10 330 12 200 1a + b) Wanted you to find the disintegration constant and the half-life. I've found those correctly. The disintegration constant is .24974 h^-1, and the half-life is 2.77 hours. (you had to take ln() and find the...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT