Question
In: Math
Among the students at a particular college, the mean number of days absent from classes is...
Among the students at a particular college, the mean number of days
absent from classes is 3.5 with a standard deviation of 1.2.
Assuming absences at the college are normally distributed determine
the probability that 3 students all missed 5 days or more
days.
Solutions
Expert Solution
Given that ,
mean = 
= 3.5
standard deviation = 
= 1.2
n = 3
=
= 3.5
=
/ 
n = 1.2/
3 = 0.6928
P(
≥ 5) = 1 - P(
≤ 5)
= 1 - P[(
-
) /
≤ (5-3.5) /0.6928 ]
= 1 - P(z ≤ 2.17)
= 1 - 0.9808 = 0.0192
probability = 0.0192
Probability =
milcah answered 5 months agoRelated Solutions
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Consider the number of days absent from a random sample of six
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Compute the arithmetic mean, geometric mean, median, and mode
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X=i=1nXin=2+3+2+4+2+56=3
mean(data2$absent)
[1] 3
Geometic Mean:
GMx=Πi=1nX11n=2∙3∙2∙4∙2∙516=2.79816
>gmean <-
prod(data2$absent)^(1/length(data2$absent))
> gmean
[1] 2.798166
Median:
X=12n+1th,
Xi2,2,2,3,4,5,
n=6=126+1th
ranked value=3.5, value=2.5 days absent
>median(data2$absent)
[1] 2.5
Mode: Most frequent value=2
> mode <-
names(table(data2$absent))
[table(data2$absent)==max(table(data2$absent))]
> mode
[1]...
The table below shows the number of students absent on the particular day of the week:...
The table below shows the number of students absent on the
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Day
M
Tu
W
Th
F
Number
111
80
85
94
99
Test if the distribution of students absent is uniform through
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Professor Venkat is on a mission to find out the average number of students absent from...
Professor Venkat is on a mission to find out the average number
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1. T The following data represents the number of days absent from school in one school...
1. T The following data represents the
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0
1
2
2
2
4
5
5
7
7
7
7
8
8
8
8
8
8
10 10
12
12 12
13
14
...
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Identify which study design is applicable for studying the following health outcomes and why?
Number of new cases of obesity among college students in Saudi Arabia in 2019. – 2 marks
The number of students with obesity who are physically active and the number of students with obesity who are physically inactive. – 2 marks
Give two difference between descriptive and analytic cross-sectional study. – 1 mark
In a simple random sample of 51 community college statistics students, the mean number of college...
In a simple random sample of 51 community college statistics
students, the mean number of college credits completed was
x=50.2 with standard deviation s = 8.3. Construct
a 98% confidence interval for the mean number of college credits
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Verify that conditions have been satisfied:
Simple random
sample?
n > 30?
Find the appropriate critical value
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Degrees...
The following data represent the number of days absent (x) and the final grade (y) for...
The following data represent the number of days absent (x) and
the final grade (y) for a sample of college students in a
statistics course at a large university.
Number of absences (x):
0
1
2
3
4
5
6
7
8 9
Final grade
(y):
89.2 86.4 83.5
81.1 78.2 73.9
64.3 71.8 65.5 66.2
Draw a scatter diagram on graph paper. The number of days
absent is the explanatory variable and the final grade is the
response variable....
The following data represent the number of days absent (x) and the final grade (y) for...
The following data represent the number of days absent (x) and
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statistics course at a large university.
Number of absences (x): 0 1 2 3 4 5 6 7 8 9
Final grade (y): 89.2 86.4 83.5 81.1 78.2 73.9 64.3 71.8 65.5
66.2
a) Draw a scatter diagram on graph paper. The number of days
absent is the explanatory variable and the final grade is the
response...
The following data represent the number of days absent per year in a population of six...
The following data represent the number of days absent per year
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10
a. Compute the population mean.
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d. Compute the mean of all the sample means. How does the mean
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The data below represent the number of days absent, x, and the final grade, y, for...
The data below represent the number of days absent, x, and the
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Number of absences, x
Final grade, y
0
88.5
1
85.6
2
82.5
3
79.9
4
76.9
5
72.4
6
62.6
7
67.1
8
64.1
9
61.1
(a) Find the least-squares regression line treating the number
of absences, x, as the explanatory variable and the final grade,
y, as...
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