Question

This is hard!!! Thanks!!

A xray photon undergoes Compton scattering from an electron initially at rest. The photon is incident from the left (-x) and is scattered backwards. a.) draw and label a sketch illustrating this collision. The initial photon energy is = 4keV. Assume that the electron energy after the collision Ee is small. b.) What is the initial photon momentum px,i in the x-direction? c.) What is the final photon momentum in the x-direction px,f after the collision? d.) Find the kinetic energy of the electrion after the collision???

Answer 1

As, Energy, E = P²/(2m)

Also, lambda = h/mv

where, lambda = (6.63 * 10^-34 * 3 * 10⁸)/(4000 * 1.6 * 10^-19)

                        = 3.1078 * 10^-10 m

Thus,   the initial photon momentum =   (6.63 * 10^-34)/(3.1078 * 10^-10)

                                                           = 2.133 * 10^-24 kg.m/s

final photon momentum in the x-direction =   (6.63 * 10^-34)/(6.2156 * 10^-10)

                                                              =   1.066 * 10^-24 kg.m/s

the kinetic energy of the electrion = (1.066 * 10^-24)²/(2 * 9.11 * 10^-31)

                                                     = 6.237 * 10^-19 J