Question

OK. So, this week we’re investigating the prokaryotic gene PPtrl, which codes for the Rbbl protein. You painstakingly derived a segment of the transcribed sequence of this gene, which is listed below.

a) What would be the mRNA sequence that corresponds with this segment?

coding

5’

G

C

T

T

A

G

C

T

G

G

A

C

T

3’

template

3’

C

G

A

A

T

C

G

A

C

C

T

G

A

5’

b) OK. So, knowing what you do about this particular PPtrl gene, describe how the process of transcription initiation would go for this gene.

Answer 1

A. 5' GCUUAGCUGGACU 3'

B. The transcription of the given gene will proceed as follows -

1. RNA polymerase will be bound by some general transcription factors initially.

2. This assembly of RNA polymerase and general transcription factors will bind to the promoter region of template DNA which is not shown in the given sequence of gene.

3. RNA polymerase will move in direction 3' to 5' and will lead to the synthesis of RNA using template DNA.

4. This will result in the formation of RNA which is complementary to the template DNA and is in direction 5' to 3'.

5. When the RNA polymerase will reach terminator sequence, it will result in the formation of hair pin like structure and RNA polymerase would fall off thereby terminating the process of transcription.

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