Question

In: Statistics and Probability

The commute time to work in the U.S. has a bell shaped distribution with a population...

The commute time to work in the U.S. has a bell shaped distribution with a population mean of 24.4 minutes and a population standard deviation of 6.5 minutes. What percentage of the population has a commute time (do not round answers): between 11.4 minutes and 37.4 minutes, inclusive? 95 less or equal to 11.4 minutes? 3 greater than or equal to 37.4 minutes? 3 greater than or equal to 24.4 minutes? between 11.4 minutes and 30.9 minutes, inclusive? between 17.9 minutes and 37.4 minutes, inclusive? between 37.4 minutes and 43.9 minutes, inclusive?

Solutions

Expert Solution

µ = 24.4, σ = 6.5

a) P(11.4 <= X <= 37.4) =
= P( (11.4-24.4)/6.5 <= (X-µ)/σ <= (37.4-24.4)/6.5 )
= P(-2 < z < 2)
= P(z < 2) - P(z < -2)
Using excel function:
= NORM.S.DIST(2, 1) - NORM.S.DIST(-2, 1)
= 0.9545 = 95.45%

b) P(X <= 11.4) =
= P( (X-µ)/σ <= (11.4-24.4)/6.5 )
= P(z <= -2)
Using excel function:
= NORM.S.DIST(-2, 1)
= 0.0228 = 2.28%

c) P(X >= 37.4) =
= P( (X-µ)/σ > (37.4-24.4)/6.5)
= P(z > 2)
= 1 - P(z < 2)
Using excel function:
= 1 - NORM.S.DIST(2, 1)
= 0.0228 = 2.28%

d) P(X > 24.4) =
= P( (X-µ)/σ > (24.4-24.4)/6.5)
= P(z > 0)
= 1 - P(z < 0)
Using excel function:
= 1 - NORM.S.DIST(0, 1)
= 0.5000 = 50%

e) P(11.4 < X < 30.9) =
= P( (11.4-24.4)/6.5 < (X-µ)/σ < (30.9-24.4)/6.5 )
= P(-2 < z < 1)
= P(z < 1) - P(z < -2)
Using excel function:
= NORM.S.DIST(1, 1) - NORM.S.DIST(-2, 1)
= 0.8186 = 81.86%

f) P(17.9 < X < 37.4) =
= P( (17.9-24.4)/6.5 < (X-µ)/σ < (37.4-24.4)/6.5 )
= P(-1 < z < 2)
= P(z < 2) - P(z < -1)
Using excel function:
= NORM.S.DIST(2, 1) - NORM.S.DIST(-1, 1)
= 0.8186 = 81.86%

g) P(37.4 < X < 43.9) =
= P( (37.4-24.4)/6.5 < (X-µ)/σ < (43.9-24.4)/6.5 )
= P(2 < z < 3)
= P(z < 3) - P(z < 2)
Using excel function:
= NORM.S.DIST(3, 1) - NORM.S.DIST(2, 1)
= 0.0214 = 2.14%


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