In: Statistics and Probability
The weight of an organ in adult males has a bell-shaped distribution with a mean of 350 grams and a standard deviation of 35 grams. Use the empirical rule to determine the following. (a) About 99.7 of organs will be between what weights? (b) What percentage of organs weighs between 280 grams and 420 grams? (c) What percentage of organs weighs less than 280 grams or more than 420 grams? (d) What percentage of organs weighs between 245 grams and 385 grams?
= mean = 350
= SD = 35
(a) By empirical rule, about 99.7 % of values will lie between 3
Substituting values, we get:
350 ( 3 X 35)
= 350 105
= ( 245, 455)
(b)
To find P(280 < X < 420):
Case 1:
X from 280 to mid value:
Z = (280 - 350)/35 = - 2
Case 2:
X from mid value to 420:
Z = (420 - 350)/35 = 2
By empirical rule, 95% of values will fall between two standard deviations from mean.
So,
Answer is:
95 %
(c)
To find P(x<280):
Z = (280 - 350)/35 = - 2
To find P(X>420):
Z = (420 - 350)/35 = 2
By empircal rule, about 5 % of values will lie outside two stadard deviations from mean.
So,
Answer is:
5 %
(d) To find P(245 < X < 385):
Case 1: X from 245 to mid value:
Z = (245 - 350)/35 = - 3
Case 2: X from mid value to 385:
Z = (385 - 350)/35 = 1
By empirical rule, 99.7/2 = 49.85 % will lie from - 3 to mid value.
By empirical rule, 68/2 = 34 % will lie from mid value to 1 .
Thus, percentage of organs weighs between 245 grams and 385 grams = 49.85 + 34 = 83.85 %