In: Physics
10 kg of air occupying a cylinder volume of 0.28 m3 is allowed
to expand isentropically
behind a piston to a pressure of 30 bar. The air is then heated at
a constant volume. Finally, the
air is cooled at a constant pressure back to its initial
conditions. The initial pressure is 60 bar.
Calculate the change in entropy, the net work done and the net heat
flow. Sketch the cycle on
the p‐v and T‐s diagrams.
The number of moles of air is
The initial temp is
For an ideal gas, an isentropic process is equal to an adiabatic process, therefore we can write
Gamma for air is 1.4
The work done in this process is given by
The following process is at constant volume, this means that the work is zero. The temperature at the end is
The heat in is equal to the change in internal energy:
The last process is an isobaric. The work done on the system is
The change in internal energy
The heat flow is then according to the first Law
The change in entropy over the cycle is zero, the net changes in work and heat are: