Find rate of change of position of mass suspended.

A mass suspended from a spring is raised a distance of 5 cm above its resting position. The mass is released at time t=0 and allowed to oscillate. After one third of a second, it is observed that the mass returns to its highest position, which was 4.5 cm above its resting position. What is the rate of change of the position of the mass at t = 2.1 seconds?

Solutions

Expert Solution

Mass suspended above its resting position at a distance = 5cm.

so amplitude (A) = |a| = 5cm

Position of Mass is modeled by equation

Y = A cos(wt)

w = (2pi)/t

to find the rate of change, we need to differentiate position of mass equation

in order to find the change.

Rate of change of position of mass suspended = -89.63cm/sec.

sunshi answered 2 years ago

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