Question

In: Chemistry

Many home barbeques are fueled with propane gas (C3H8). What mass of carbon dioxide (in kg)...

Many home barbeques are fueled with propane gas (C3H8).


What mass of carbon dioxide (in kg) is produced upon the complete combustion of 18.9 L of propane (approximate contents of one 5-gallon tank)? Assume that the density of the liquid propane in the tank is 0.621 g/mL. (Hint: Begin by writing a balanced equation for the combustion reaction.)

m = ______________kg

Solutions

Expert Solution

Given volume of the propane is , V = 18.9 L = 18.9x1000 mL

         density of the propaneis , d = 0.621 g/mL

So mass of propane , m = density x volume

                                      = 0.621 x 18.9x1000 g

                                      = 11736.9 g

The balanced Equation of combustion of propane is

        C3H8 + 5O2 3CO2 + 4H2O

Molarmass of propane,C3H8 is = (3xAt.mass of C ) + ( 8xAt.mass of H )

                                                = ( 3x12) + ( 8x1)

                                               = 44 g/mol

MOlar mass of carbon dioxide ,CO2 is = At.mass of C + (2xAt.mass of O)

                                                             = 12 + (2x16)

                                                            = 44 g/mol

According to the balanced Equation ,

1 mole of propane produces 3 moles of CO2

                                  OR

44 g of propane produces 3x44 g of CO2

11736.9 g of propane produces 3x11736.9 g of CO2

                                                    = 35210.7 g

                                                   = 35.2 kg                 Since 1 kg = 1000 g

So the mass of carbon dioxide is produced upon the complete combustion of propane is 35.2 kg

       


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