A gaseous mixture of propane, carbon dioxide and hydrogen with a mixture total mass m =...

A gaseous mixture of propane, carbon dioxide and hydrogen with a mixture total mass m = 188 g occupies a volume V = 33 L at t = 88

Solutions

Expert Solution

P=9 atm

V= 33 L

T= 88 oC =(273+88) K = 361 K

use:

P*V =n *R*T

9*33 = n* 0.0821* 361

n= 10 mol

so , Total number of moles =10

Let mass of Hydrogen be x gm

Number of moles of Hydrogen = mass/ molar mass = x/2

Then combined mass of propane and carbon dioxide = (188-x) gm

Total number of moles of propane and carbon dioxide combined = mass/molar mass = (188-x)/44

so, total number of moles = x/2 + (188-x)/44

equate to total number of moles found in 2 ways:

x/2 + (188-x)/44 =10

(22x+188-x)/44=10

21x+188 = 440

x=12

so, number of moles of hydrogen = 12/2 = 6mol

partial pressure of Hyrogen = Total pressure * number of moles of hydrogen /total number of moles

= 9*6/10

= 5.4 atm

Answer: 5.4 atm

queen_honey_blossom answered 8 months ago

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