Question
In: Statistics and Probability
Exercise 3 The data in the table represent the "Exam Scores" for two random samples of...
Exercise 3
The data in the table represent the "Exam Scores" for two random samples of students. The first group of = 6 students were under active-learning course, and the second group of = 6 students were under traditional lecturing. Note that the standard deviations in the Active group is = 3.43 and in the Traditional group is = 3.03.
|
Active learning |
Traditional learning |
|
0 |
7 |
|
5 |
0 |
|
7 |
8 |
|
8 |
2 |
|
0 |
4 |
|
3 |
3 |
Please answer the following questions underneath each question.
1. Which test is appropriate to compare the Exam-Scores in the two groups of students?
Answer:
2. Conduct the steps of this test
(please enumerate and write all the steps of your answer below)
Step 1:
3. State your conclusion in the context of this study
Solutions
Expert Solution
Here we will use t distribution because sample size is small.
orchestra answered 2 years agoRelated Solutions
Exercise 3 The data in the table represent the "Exam Scores" for two random samples of...
Exercise 3
The data in the table represent the "Exam Scores" for two random
samples of students. The first group of n1 = 6
students were under active-learning course, and the second group of
n2 = 6 students were under traditional lecturing.
Note that the standard deviations in the Active group is
s1= 3.43 and in the Traditional group is
s2 = 3.03.
Active learning
Traditional learning
0
7
5
0
7
8
8
2
0
4
3
3
Please...
The two data sets in the table below are dependent random samples. The population of (...
The two data sets in the table below are dependent random
samples. The population of ( x − y ) (x-y) differences is
approximately normally distributed. A claim is made that the mean
difference ( x − y ) (x-y) is less than -31.4.
X 25 32 48 37 39 34 37
Y 73 64 66 80 78 67 84
For each part below, enter only a numeric value in the answer
box. For example, do not type "z ="...
The following data represent petal lengths (in cm) for independent random samples of two species of...
The following data represent petal lengths (in cm) for
independent random samples of two species of Iris.
Petal length (in cm) of Iris virginica:
x1; n1 = 35
5.1
5.9
6.4
6.1
5.1
5.5
5.3
5.5
6.9
5.0
4.9
6.0
4.8
6.1
5.6
5.1
5.6
4.8
5.4
5.1
5.1
5.9
5.2
5.7
5.4
4.5
6.4
5.3
5.5
6.7
5.7
4.9
4.8
5.7
5.2
Petal length (in cm) of Iris setosa:
x2; n2 = 38
1.6
1.9
1.4
1.5
1.5
1.6...
The following data represent petal lengths (in cm) for independent random samples of two species of...
The following data represent petal lengths (in cm) for
independent random samples of two species of Iris.
Petal length (in cm) of Iris virginica:
x1; n1 = 35
5.1
5.9
6.1
6.1
5.1
5.5
5.3
5.5
6.9
5.0
4.9
6.0
4.8
6.1
5.6
5.1
5.6
4.8
5.4
5.1
5.1
5.9
5.2
5.7
5.4
4.5
6.4
5.3
5.5
6.7
5.7
4.9
4.8
5.9
5.1
Petal length (in cm) of Iris setosa:
x2; n2 = 38
1.5
1.9
1.4
1.5
1.5
1.6...
The following data represent petal lengths (in cm) for independent random samples of two species of...
The following data represent petal lengths (in cm) for
independent random samples of two species of Iris.
Petal length (in cm) of Iris virginica:
x1; n1 = 35
5.1
5.6
6.3
6.1
5.1
5.5
5.3
5.5
6.9
5.0
4.9
6.0
4.8
6.1
5.6
5.1
5.6
4.8
5.4
5.1
5.1
5.9
5.2
5.7
5.4
4.5
6.4
5.3
5.5
6.7
5.7
4.9
4.8
5.9
5.2
Petal length (in cm) of Iris setosa:
x2; n2 = 38
1.5
1.9
1.4
1.5
1.5
1.6...
The following data represent petal lengths (in cm) for independent random samples of two species of...
The following data represent petal lengths (in cm) for
independent random samples of two species of Iris. Petal length (in
cm) of Iris virginica: x1; n1 = 35 5.3 5.7 6.5 6.1 5.1 5.5 5.3 5.5
6.9 5.0 4.9 6.0 4.8 6.1 5.6 5.1 5.6 4.8 5.4 5.1 5.1 5.9 5.2 5.7 5.4
4.5 6.4 5.3 5.5 6.7 5.7 4.9 4.8 5.8 5.2 Petal length (in cm) of
Iris setosa: x2; n2 = 38 1.5 1.7 1.4 1.5 1.5 1.6...
The following data represent petal lengths (in cm) for independent random samples of two species of...
The following data represent petal lengths (in cm) for
independent random samples of two species of Iris. Petal length (in
cm) of Iris virginica: x1; n1 = 35 5.1 5.6 6.2 6.1 5.1 5.5 5.3 5.5
6.9 5.0 4.9 6.0 4.8 6.1 5.6 5.1 5.6 4.8 5.4 5.1 5.1 5.9 5.2 5.7 5.4
4.5 6.4 5.3 5.5 6.7 5.7 4.9 4.8 5.7 5.1 Petal length (in cm) of
Iris setosa: x2; n2 = 38 1.6 1.9 1.4 1.5 1.5 1.6...
The following data represent petal lengths (in cm) for independent random samples of two species of...
The following data represent petal lengths (in cm) for
independent random samples of two species of Iris. Petal length (in
cm) of Iris virginica: x1; n1 =
35 5.1 5.8 6.5 6.1 5.1 5.5 5.3 5.5 6.9 5.0 4.9 6.0 4.8 6.1 5.6
5.1 5.6 4.8 5.4 5.1 5.1 5.9 5.2 5.7 5.4 4.5 6.4 5.3 5.5 6.7 5.7 4.9
4.8 5.9 5.1
Petal length (in cm) of Iris setosa: x2; n2 =
38 1.6 1.8 1.4 1.5 1.5 1.6...
Problem 1 The following table lists data on the participation scores and midterm exam scores for...
Problem 1
The following table lists data on the participation scores and
midterm exam scores for 23 students who took the Accounting Theory
class in Spring 2019.
Student Number
Participation Score
Midterm Score
1
5
75
2
6.5
84
3
6.5
73
4
7
96
5
7.5
83
6
7.5
88
7
7.5
75
8
8
75
9
8.5
82.5
10
8.5
89
11
8.5
90
12
8.5
91
13
9
92
14
9
81.5
15
9
95
16
9...
Given in the table are the course evaluation scores for random samples of male professors and...
Given in the table are the course evaluation scores for random
samples of male professors and female professors. Assume that the
two samples are selected from normal distributed populations and do
not assume that the population standard deviations are equal. Use
0.05 significance level to test the claim that the male professors
and female professors course evaluation scores are from the
population with the same mean. Let the male professor as the first
population.
Mean
Standard deviation
Simple size
Male...
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