Question

The college Physical Education Department offered an Advanced First Aid course last summer. The scores on the comprehensive final exam were normally distributed, and the zscores for some of the students are shown below.

Robert, 0.95	Juan, 1.68	Susan, –1.97
Joel, 0.00	Jan, –0.91	Linda, 1.77

(d) If the mean score was μ = 146 with standard deviation σ = 23, what was the final exam score for each student? (Round your answers to the nearest whole number.)

Robert
Joel
Jan
Juan
Susan
Linda

Answer 1

Solution :

Given that ,

mean = = 146

standard deviation = =23

(A) robert = z =0.95

Using z-score formula  

x = z +

x = 0.95 *23+146

x = 168

(b) joel = z =0.00

Using z-score formula  

x = z +

x =0.00 *23+146

x = 146

(c) jan = z =-0.91

Using z-score formula  

x = z +

x = -0.91 *23+146

x = 125

(d) juan = z =1.68

Using z-score formula  

x = z +

x =1.68 *23+146

x = 145

(e) susan = z =-1.97

Using z-score formula  

x = z +

x =-1.97 *23+146

x = 101

(F)linda = z =1.77

Using z-score formula  

x = z +

x =1.77 *23+146

x = 187