In: Math
A sample of n=18 observations is drawn from a normal population with μ=1040 and σ=230. Find each of the following:
A. P(X¯>1159)
Probability =
B. P(X¯<953)
Probability =
C. P(X¯>996)
Probability =
olution :
Given that,
mean =
=1040
standard deviation =
= 230
n = 18

= 1040

= (
/n) = (230 /
18 ) = 54.2115
A ) (
> 1159 )
= 1 - P (
< 1159)
= 1 - P (
- 
/
) < (1159
- 1040 /54.2115)
= 1 - P( z < 119 / 54.2115 )
= 1 - P ( z < 2.20 )
Using z table
= 1 - 0.9861
= 0.0139
Probability = 0.0139
B ) (
< 953)
P (
- 
/
) < (953
- 1040 /54.2115)
P( z < - 87 / 54.2115 )
P ( z < -1.60 )
Using z table
= 0.0548
Probability = 0.0548
C ) (
> 996 )
= 1 - P (
< 996)
= 1 - P (
- 
/
) < (
996 - 1040 /54.2115)
= 1 - P( z < - 44 / 54.2115 )
= 1 - P ( z < - 0.81 )
Using z table
= 1 - 0.2090
= 0.7910
Probability = 0.7910