In: Math
A sample of n=18 observations is drawn from a normal population with μ=1040 and σ=230. Find each of the following:
A. P(X¯>1159)
Probability =
B. P(X¯<953)
Probability =
C. P(X¯>996)
Probability =
olution :
Given that,
mean = 
 =1040
standard deviation = 
 = 230
n = 18

 = 1040

  =  (
/n) = (230 / 
18 ) = 54.2115
A ) ( 
   > 1159 )
= 1 - P ( 
 < 1159)
= 1 - P ( 
 - 
/
)  <  (1159
- 1040 /54.2115)
= 1 - P( z < 119 / 54.2115 )
= 1 - P ( z < 2.20 )
Using z table
= 1 - 0.9861
= 0.0139
Probability = 0.0139
B ) ( 
 < 953)
P ( 
 - 
/
)  <  (953
- 1040 /54.2115)
P( z < - 87 / 54.2115 )
P ( z < -1.60 )
Using z table
= 0.0548
Probability = 0.0548
C ) ( 
   > 996 )
= 1 - P ( 
 < 996)
= 1 - P ( 
 - 
/
)  <  (
996 - 1040 /54.2115)
= 1 - P( z < - 44 / 54.2115 )
= 1 - P ( z < - 0.81 )
Using z table
= 1 - 0.2090
= 0.7910
Probability = 0.7910