In: Statistics and Probability
A sample of n=23 observations is drawn from a normal population with μ=1030 and σ=210. Find each of the following:
A. P(X¯>1117)
Probability =
B. P(X¯<964)
Probability =
C. P(X¯>1012)
Probability =
Solution :
Given that ,
mean = = 1030
standard deviation = = 210
= / n = 210 / 23 = 43.7880
A.
P( > 1117) = 1 - P( < 1117)
= 1 - P[( - ) / < (1117 - 1030) / 43.7880]
= 1 - P(z < 1.99)
= 1 - 0.9767
= 0.0233
Probability = 0.0233
B.
P(x 964)
= P[(x - ) / (964 - 1030) / 43.7880]
= P(z -1.51)
= 0.0655
Probability = 0.0655
C.
P( > 1012) = 1 - P( < 1012)
= 1 - P[( - ) / < (1012 - 1030) / 43.7880]
= 1 - P(z < -0.41)
= 1 - 0.3409
= 0.6591
Probability = 0.6591