Question
In: Statistics and Probability
A sample of n = 36 observations is drawn from a normal population, with = 500 and =...
A sample of n = 36 observations is drawn from a normal population, with = 500 and = 42. Find P(500 < X̅ < 510).
| a. |
0.0764 |
|
| b. |
0.8756 |
|
| c. |
0.9236 |
|
| d. |
0.7556 |
|
| e. |
0.4236 |
Solutions
Expert Solution
Solution :
Given that ,
mean = 
= 500
standard deviation = 
= 42
n = 36
= 500
= /
P(500< <510
) = P[(500-500) /7 < (
-
) / < (510-500) /7 )]
= P(0 < Z <1.43 )
= P(Z < 1.43) - P(Z < 0)
Using z table
=0.9236-0.5
=0.4236
orchestra answered 3 years agoRelated Solutions
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